project-euler

Problem 6: Sum square difference

Question

The sum of the squares of the first ten natural numbers is, 1² + 2² + … + 10² = 385

The square of the sum of the first ten natural numbers is, (1 + 2 + … + 10)² = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first n natural numbers and the square of the sum.

Algorithm(s)

To Do

Solution(s)

JavaScript

const sumSquareDifference = n => {
    return (3 * Math.pow(n, 4) + 2 * Math.pow(n, 3) - 3 * Math.pow(n, 2) - 2 * n) / 12
}

console.log(sumSquareDifference(100)) // output: 25164150

Python

def sumSquareDifference(n):
    return (3 * n**4 + 2 * n**3 - 3 * n**2 - 2 * n) / 12

print(sumSquareDifference(100)) # output: 25164150

C++

// To Do

C#

// To Do

GoLang

// To Do